Summary

Describe the Bug

Await can be outside of a function if is in code that won't be executed automatically (ex: async generators).

await statement outside of a function

This code is correct, yet ruff complains:

import asyncio

async def test2():
    return "test"

async def a_gen():
    for i in range(3):
        yield test2()

a = (await cor async for cor in a_gen()) # `await` statement outside of a function F704

async def main():
    async for i in a:
        print(i)

if __name__ == "__main__":
    asyncio.run(main())

I suggest changing F704 so awaits are ok inside async generators that are basically syntax sugar of a function.

of course for now we can do the equivalent:

async def a():
    for cor in a_gen():
        yield await cor

Version

No response