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dimension error when multiplying variable/expression with numpy float #478
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I have confirmed this bug exists on the lastest release of Linopy.
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I have confirmed this bug exists on the current
masterbranch of Linopy.
Issue Description
When multiplying a variable or expression with a scalar numpy float, I receive a ValueError: different number of dimensions on data and dims: 0 vs 1.
Reproducible Example
import pandas as pd
from linopy import Model
import numpy as np
m = Model()
b = np.float64(5.0)
index = pd.Index(["a", "b", "c"], name="index")
m.add_variables(lower=0, name="var", coords=[index])
expr = m.variables["var"] * b
# workaround
expr = m.variables["var"] * b.item()Expected Behavior
No ValueError in expr = m.variables["var"] * b
Installed Versions
Details
Bottleneck==1.5.0 click==8.2.1 cloudpickle==3.1.1 colorama==0.4.6 dask==2025.7.0 deprecation==2.1.0 fsspec==2025.7.0 linopy==0.5.5 locket==1.0.0 numexpr==2.11.0 numpy==2.3.2 packaging==25.0 pandas==2.3.1 partd==1.4.2 polars==1.31.0 python-dateutil==2.9.0.post0 pytz==2025.2 PyYAML==6.0.2 scipy==1.16.1 setuptools==78.1.1 six==1.17.0 toolz==1.0.0 tqdm==4.67.1 tzdata==2025.2 wheel==0.45.1 xarray==2025.7.1Reactions are currently unavailable
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bugSomething isn't workingSomething isn't working