2.1 Method Overloading<\/h3>\n Two methods are said to overloaded if they have the same method name and different parameters i.e either two methods should have a different number of parameters or the data types of the parameters of two methods must be different.<\/p>\n
Let us understand this with a coding snippet below:<\/p>\n
\/\/ program to show method overloading in java\npackage com.javacodegeeks.snippets.core;\n\nclass Example1\n{\n\tpublic static String add(String s1, String s2) \/\/method to perform String concatenation\n\t{\n\t\treturn s1+s2;\n\t}\n\n\tpublic static int add(int a,int b) \/\/method to perform int addition\n\t{\n\t\treturn a+b;\n\t}\n\tpublic static void main(String[] args) {\n\t\t\n\t\tSystem.out.println(add(10,30)); \/\/calls add function with int params\n\t\tSystem.out.println(add(\"Rajesh\",\"Kumar\")); \/\/calls add function with String params\n\t}\n}<\/pre>\nOutput<\/em><\/span><\/p>\n40\nRajeshKumar\n<\/pre>\nIn this example, when we pass String parameters to the method add, add() method at Line 6 is getting executed. This method returns the String after concatenation of both Strings s1 and s2. But when we passed integer values to the add method, add() method at Line 11 is getting executed and it returns the addition of two values. Here we used the same method name add, we are able to interact with two functionalities based on the parameters which are passed.<\/p>\n
The compiler is able to recognize these method calls and therefore it is also called Compile time Polymorphism.<\/p>\n
2.2 Method Overriding<\/h3>\n In Method Overriding, during Inheritance, a child class provides its own implementation to the Parent’s method, thereby overriding the implementation of the parent. Two methods are said to be overridden only if they have the same Signature, that is, the same name and same parameters.<\/p>\n
In this context, the Parent’s method is called an Overridden method and the Child’s method is called an Overriding method.<\/p>\n
Let us understand what does below coding snippet contains :<\/p>\n
\nShape<\/code> class has two methods, drawShape()<\/code> and eraseShape()<\/code>.<\/li>\nClasses Circle<\/code>, Square<\/code> and Triangle<\/code> extend Shape<\/code> and override its two methods, each one in a different way.<\/li>\nRandomShapeGenerator<\/code> class has a method, Shape next()<\/code> that randomly creates one of the above classes, Circle<\/code>, Square<\/code> and Triangle<\/code>.<\/li>\nWe create a new RandomShapeGenerator<\/code> instance and a new Shape<\/code> array.<\/li>\nWe fill the Shape<\/code> array, by creating random shapes, using the next()<\/code> method of RandomShapeGenerator<\/code>.<\/li>\nThen we call drawShape()<\/code> method, so each time the method of the object created randomly is called.<\/li>\n<\/ul>\nLet us take a look at the code snippet that follows: <\/p>\n
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package<\/code> com.javacodegeeks.snippets.core;<\/code><\/div>\n <\/div>\n
import<\/code> java.util.Random;<\/code><\/div>\n <\/div>\n
class<\/code> Shape {<\/code><\/div>\n <\/div>\n
<\/code>void<\/code> drawShape() {<\/code><\/div>\n <\/code>}<\/code><\/div>\n <\/div>\n
<\/code>void<\/code> eraseShape() {<\/code><\/div>\n <\/code>}<\/code><\/div>\n}<\/code><\/div>\n <\/div>\n
class<\/code> Circle <\/code>extends<\/code> Shape {<\/code><\/div>\n <\/div>\n
<\/code>@Override<\/code><\/div>\n <\/code>void<\/code> drawShape() {<\/code><\/div>\n <\/div>\n
<\/code>System.out.println(<\/code>\"Circle.draw()\"<\/code>);<\/code><\/div>\n <\/code>}<\/code><\/div>\n <\/div>\n
<\/code>@Override<\/code><\/div>\n <\/code>void<\/code> eraseShape() {<\/code><\/div>\n <\/div>\n
<\/code>System.out.println(<\/code>\"Circle.erase()\"<\/code>);<\/code><\/div>\n <\/code>}<\/code><\/div>\n}<\/code><\/div>\n <\/div>\n
class<\/code> Square <\/code>extends<\/code>
![\"\"](\"https:\/\/examples.javacodegeeks.com\/wp-content\/uploads\/2022\/07\/Java-Polymorphism-Tutorial-1024x576.jpg\")
<\/a>![\"polymorphism](\"http:\/\/examples.javacodegeeks.com\/wp-content\/uploads\/2012\/12\/java-logo.jpg\"){kind=logo}
<\/figure>\n<\/div>\n